Hcf of 1305 4665 6905
WebWhat is the HCF of a 2 b 4 + 2 a 2 b 2 and (ab) 7 - 4a 2 b 2? Options A. ab B. a2 b3 C. a2 b2 D. a3 b2 Show Answer Scratch Pad Discuss 7. Find the largest number which divides 1305, 4665 and 6905 leaving same remainder in each case. Also, find the common Remainder. Options A. 1210, 158 B. 1120, 158 C. 1120, 185 D. 1210, 185 Show Answer … WebAug 22, 2024 · 6905 - 1305 = 5600. 6905 - 4665 = 2240. 4665 - 1305 = 3360. Hence, the greatest number which divides 1305, 4665 and 6905 and gives the same remainder, N. = …
Hcf of 1305 4665 6905
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WebN = H.C.F. of (4665 - 1305), (6905 - 4665) and (6905 - 1305) = H.C.F. of 3360, 2240 and 5600 = 1120. Sum of digits in N = ( 1 + 1 + 2 + 0 ) = 4. Subject: HCF and LCM - … Web(4665 - 1305)=3360, (6905 - 4665)=2240 and (6905 - 1305)=5600 3360:2240:5600 1120:1120:1120 Let the numbers be represented as . 1305 = Na + d -----(1) where q is the remainder ... Now we need to find HCF of (3360 , 5600 , 2240) , that is 80 which is equal to value of N. Thus N is 1120. Suggest Corrections. 0. Similar questions.
WebJun 22, 2024 · So, let's take out the H.C.F of 1305, 4665 and 6905 (leaving the same remainder) = H.C.F of (4665 - 1305), ( 6905- 4665) and ( 6905- 1305) = H.c.f of 3360, 2240 and 5600 which is= 1120. Sum of digits of 1120= (1+1+2+0)= 4. Answer=4. Find Math textbook solutions? Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 … WebHCF and LCM Questions & Answers : The L.C.M of 22, 54, 108, 135 and 198 is ... If N is the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. What is the sum of the digits of N ? A) 6 B) 8 C) 4 D) 9 ...
WebUsing Rule 7, The greatest number N = HCF of (1305 – x ), (4665 – x) and (6905 – x), where x is the remainder = HCF of (4665 – 1305), (6905– 4665) and (6905 – 1305) = … WebGiven that. x = 1305, y = 4665, z = 6905. Then , x - y = 1305 - 4665 = 3360. y - z] = 4665 - 6905 = 2240. z - x = 6905 -1305 = 5600. ∴ Required number = HCF of 3360, 2240 …
Web135 = 3 × 3 × 3 × 5. Find the prime factorization of 405. 405 = 3 × 3 × 3 × 3 × 5. To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 3 × 3 × 3 …
WebHCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily for 1305, 6905 i.e. 5 the largest integer that leaves a remainder zero … short story on booksWebLet N be the largest integer that divides 1305, 4665, and 6905 without leaving the same residual in each case. Then in N, the total of the digits is: a. 4 b. 5 c. 6 d. 8 5. The greatest four-digit number that is divisible by 15, 25, 40, and 75 is: a. 9000 b. 9400 c. 9600 d. 9800 6. The sum of two integers equals 4107. sapcr prove up texasWebHighest Common Factor of 4665, 1305, 6905 using Euclid's algorithm. HCF Calculator using the Euclid Division Algorithm helps you to find the Highest common factor (HCF) easily … sap crystal report 13.0.2000.0WebLet N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: A. 4 B. 5 C. 6 D. 8 Asked In CSC … short story on bullyingWebJul 2, 2024 · 4665 - 1305 = 3360 6905 - 4665 = 2240 6905 - 1305 = 5600 HCF of 3360, 2240 and 5600 = 1120 Then sum of the digits in N = 1 + 1 + 2 + 0 = 4 ∴ The sum of the digits in N is 4 Download Solution PDF Latest Odisha … short story on birds with moralWebJun 22, 2024 · Aishwarya06. Since the remainder is same in each case, we will use the following formula-. H.C.F (x, y, z)= H.C.F of (x -y), (y- z), ( z-x) So, let's take out the … short story on charityWebdivides 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: a) 4 b) 5 c) 6 d) 8 Asked In TCS shikha (8 years ago) Solved harvinder … short story on child marriage